This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers Your example code will not compile, because the ID property of your class needs to be an int instead of a string and you need to put double quotes around your string values, like this: public class Checkit { public int ID { get; set; } public string b { get; set; } public
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 你的示例代码不会被编译，因为你的类的ID属性需要是一个int而不是一个string ，你需要在你的字符串值中加双引号，如下所示： public class Checkit { public int ID { get; set; } public string b { get; set; } public string c { get; set; } } List<Checkit> Lst_Ch = new List<Checkit>(); Lst_Ch.Add(new Checkit {
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers You can use OrderBy for that: @foreach (var LedenA in Model.Groepen.AllMembers.OrderBy(x => x.Anaam)) { } If you want to sort on the first name after that, use ThenBy : @foreach (var LedenA in Model.Groepen.AllMembers.OrderBy(x => x.Anaam).ThenBy(x => x.Vnaam)) { }
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 您可以使用OrderBy ： @foreach (var LedenA in Model.Groepen.AllMembers.OrderBy(x => x.Anaam)) { } 如果您想在此之后排序第一个名称，请使用ThenBy ： @foreach (var LedenA in Model.Groepen.AllMembers.OrderBy(x => x.Anaam).ThenBy(x => x.Vnaam)) { }
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers you would need to calculate a key to sort by List<Test> ordered = values.OrderBy(v => v.Value.StartsWith(">") ? "ZZ" + v.Value : v.Value ).ToList(); "ZZ" is an arbitrary key that will sort the values starting with ">" after all English ter
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 你需要计算一个键来排序 List<Test> ordered = values.OrderBy(v => v.Value.StartsWith(">") ? "ZZ" + v.Value : v.Value ).ToList(); “ZZ”是一个任意的键，它将按照所有英文术语排序以“>”开头的值。 （作为字母表中的最后一个字母，并且没有以两个Z开始的英文单词）。 SInce“>”的字节值低于任何一个Z不够的字母
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers Pretty standard, simple linq. var candleList = candleList.Distinct().OrderBy(x => x.date).ToList(); As Adam mentioned below, this will only remove duplicate instances within the list, not instances which all of the same property values. You can implement your own IEqualityCompar
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 漂亮的标准，简单的linq。 var candleList = candleList.Distinct().OrderBy(x => x.date).ToList(); 正如Adam在下面提到的，这只会删除列表中的重复实例，而不是具有所有相同属性值的实例。 您可以实现自己的IEqualityComparer<Candle>作为通过它的选项。 的IEqualityComparer 你可能想看看msdn，并阅读Linq和Enumerable方法：MS
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers Using LINQ: tocke = tocke.OrderBy(x=> x.t.X).ToList(); Make t public. Direct solution without LINQ (just list sorting, no additional list creation). Providing that t is made public: tocke.Sort((left, right) => left.t.X - right.t.X); But the best way, IMHO, is to make c
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 使用LINQ： tocke = tocke.OrderBy(x=> x.t.X).ToList(); 让t公众。 没有LINQ的直接解决方案（只是列表排序，没有额外的列表创建）。 提供这个t是公开的： tocke.Sort((left, right) => left.t.X - right.t.X); 但是，恕我直言，最好的办法是让class tocka可比： class tocka: IComparable<tocka> { ... public int C
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers This might be inefficient, but you could add a DateTime property to your MyEvent class that converts StartDate to a DateTime and sort on that: public class MyEvent { public int EventId{get;set;} public MyDate StartDate{get;set;} public DateTime MyStartDate { get { return D
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 这可能效率低下，但是您可以将DateTime属性添加到MyEvent类中，该类将StartDate转换为DateTime并对其进行排序： public class MyEvent { public int EventId{get;set;} public MyDate StartDate{get;set;} public DateTime MyStartDate { get { return DateTime.Parse(StartDate.MMDDYYYYHHMMSS); } } } var sorted = myEvents.Order
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers Check Sort method, that takes Comparison<T> . Avaliable from .NET 2.0 var list = new List<Point>{ /* populate list */ }; list.Sort(Comparison); public int Comparison (Point a, Point b) { //do logic comparison with a and b return -1; } 你需要使用一个委托，几乎是
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 检查Sort方法，该方法需要Comparison<T> 。 从.NET 2.0可用 var list = new List<Point>{ /* populate list */ }; list.Sort(Comparison); public int Comparison (Point a, Point b) { //do logic comparison with a and b return -1; } 你需要使用一个委托，几乎是一个单一的:) list.Sort(delegate(Point p1, Point p2)
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers 尝试这个： List<Person> SortedList = people.OrderBy(o=>o.Age).ToList(); people.Sort((p1, p2) => { return p1.Age - p2.Age; });
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 尝试这个： List<Person> SortedList = people.OrderBy(o=>o.Age).ToList(); people.Sort((p1, p2) => { return p1.Age - p2.Age; });
This question already has an answer here: How to Sort a List<T> by a property in the object 19 answers LINQ： pointsOfList = pointsOfList.OrderByDescending(p => p.X).ToList(); pointsOfList.OrderBy(p=>p.x).ThenBy(p=>p.y) 这个简单的控制台程序可以： class Program { static void Main(string[] args) { List<Points> pointsOfList = new List<Points>(){
这个问题在这里已经有了答案： 如何按对象中的属性排序列表<T> 19答案 LINQ： pointsOfList = pointsOfList.OrderByDescending(p => p.X).ToList(); pointsOfList.OrderBy(p=>p.x).ThenBy(p=>p.y) 这个简单的控制台程序可以： class Program { static void Main(string[] args) { List<Points> pointsOfList = new List<Points>(){ new Points() { x = 9, y = 3
Can I improve the following function under CUDA ? What the function does is, Given a min and max , ELM1 and ELM , check if any three numbers of array ans[6] are found in any row, from min to max , in array D1 , D2 , D3 , D4 , D5 , D6 , if found return 1. I tried using loops , OR -ing, AND -ing, replacing goto with flag etc. etc. But this seems to be the fastest way. __device__ bool THREEA
我可以在CUDA下改进以下功能吗？ 该功能所做的是， 给定一个min和max ， ELM1和ELM ，检查是否阵列的任何三个数字ans[6]中的任何行被找到，从min到max ，在阵列D1 ， D2 ， D3 ， D4 ， D5 ， D6 ，若发现返回1 。 我尝试使用loops ， OR -ing， AND -ing，用标志等替换goto等。但这似乎是最快的方法。 __device__ bool THREEA(unsigned int n0, unsigned int n,unsigned int* ST1,unsigned int* D1, unsigned int* D2,un