This question already has an answer here: Do I cast the result of malloc? 27 answers I assume you mean something like this: int *iptr = (int*)malloc(/* something */); And in C, you do not have to (and should not) cast the return pointer from malloc . It's a void * and in C, it is implicitly converted to another pointer type. int *iptr = malloc(/* something */); Is the preferred
这个问题在这里已经有了答案： 我输入malloc的结果吗？ 27个答案 我假设你的意思是这样的： int *iptr = (int*)malloc(/* something */); 而在C中，你不必（也不应该）从malloc投下返回指针。 它是一个void *并且在C中，它被隐式转换为另一个指针类型。 int *iptr = malloc(/* something */); 是首选的形式。 这不适用于C ++，它不共享相同的void *隐式强制转换行为。 您不应该在C中使用malloc()的返回值。这
This question already has an answer here: Do I cast the result of malloc? 27 answers No need to cast return value of malloc as its return type is void* . Can someone explain why do some programmers use (*char) in front of the malloc? They are doing wrong (most probably) by casting it (in good programmers opinion). As wiki says: malloc returns a void pointer ( void * ), which indicate
这个问题在这里已经有了答案： 我输入malloc的结果吗？ 27个答案 无需转换malloc返回值，因为它的返回类型是void* 。 有人可以解释为什么一些程序员在malloc前使用（* char）？ 他们做错了（最有可能的）是通过投掷它（在好的程序员看来）。 正如wiki所说： malloc返回一个void指针（ void * ），它表示它是一个指向未知数据类型区域的指针。 由于强类型系统，在C ++中需要使用强制类型转换，而在C 1中则不然 。缺
I'm currently testing out Parallel for C#. Generally it works fine, and using parallel is faster than the normal foreach loops. However, at times (like 1 out of 5 times), my CPU will reach 100% usage, causing parallel tasks to be very slow. My CPU setup is i5-4570 with 8gb ram. Does anyone have any idea why this problem occurs? Below are the codes I used to test out the function
我目前正在测试Parallel for C＃。 一般来说，它工作正常，使用并行比正常的foreach循环更快。 但是，有时（比如5次中的1次），我的CPU会达到100％的使用率，导致并行任务非常慢。 我的CPU设置是i5-4570和8GB内存。 有谁知道为什么会出现这个问题？ 以下是我用来测试该功能的代码 // Using normal foreach ConcurrentBag<int> resultData = new ConcurrentBag<int>(); St
I am new to C# and SyncFusion and would really appreciate your help. I need to have the correct records shown in TreeViewPresenter(TreeViewAdv) after filtering gridGroupingControl . First I thought about to get the filters with: detailGroupingControl.TableDescriptor.RecordFilters and to set these filters in the TreeViewPresenter but it seems that it doesn't work like that. Are there an
我是C＃和SyncFusion的新手，非常感谢您的帮助。 在过滤gridGroupingControl之后，我需要在TreeViewPresenter(TreeViewAdv)显示正确的记录。 首先，我想要获得过滤器： detailGroupingControl.TableDescriptor.RecordFilters 并在TreeViewPresenter设置这些过滤器，但它似乎不起作用。 有没有简单的方法来过滤与gridGroupingControl具有相同过滤标准的树？ 如果要将RecordFilters从一个TreeView节点添加到另一个TreeVie
I keep getting this warning c:9:80: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast] printf("Char= %c ASCII = %i hex = %x pointer = %p n", i, i, i , (void*)i ); Code #include<stdio.h> int main (void) { int *i; for (int i = 75; i < 75 + 26; i++) { printf("Char= %c ASCII = %i hex = %x pointer = %p n", i, i, i , (voi
我不断收到这个警告 c：9：80：警告：从不同大小的整数转换为指针[-Wint-to-pointer-cast] printf（“Char =％c ASCII =％i hex =％x pointer =％p n”，i，i，i，（void *）i）; 码 #include<stdio.h> int main (void) { int *i; for (int i = 75; i < 75 + 26; i++) { printf("Char= %c ASCII = %i hex = %x pointer = %p n", i, i, i , (void*)i ); } return(0); } 我
I am getting warning: cast from pointer to integer of different size at line return (Node *) ((unsigned int)(a) ^ (unsigned int)(b)); . How can I get rid of it ? The intent of XORing the addresses is to implement a XORed link list which is a doubly link list and it consists of only one field to traverse back and forth in the list. The npx field contained the difference between the pointer
我正进入（状态 警告：从指针转换为不同大小的整数 在线return (Node *) ((unsigned int)(a) ^ (unsigned int)(b)); 。 我怎样才能摆脱它？ 异或地址的目的是实现一个XORed链接列表，它是一个双向链接列表，并且它只包含一个在列表中来回移动的字段。 npx字段包含指向下一个节点的指针和指向前一个节点的指针之间的差异。 指针差异通过XORing计算。 typedef struct _node { int data; struct _node *npx; }N
I have this piece of code: ... #include <stdlib.h> ... typedef struct tToken { tState state; //stav lexemu char *data; //hodnota lexemu int row; //radek lexemu int column; //sloupec lexemu }tToken; tToken token; ... void *gcMalloc(int dataSize){ ... void *AllocatedData = (void*)malloc(dataSize); return Allocat
我有这段代码： ... #include <stdlib.h> ... typedef struct tToken { tState state; //stav lexemu char *data; //hodnota lexemu int row; //radek lexemu int column; //sloupec lexemu }tToken; tToken token; ... void *gcMalloc(int dataSize){ ... void *AllocatedData = (void*)malloc(dataSize); return AllocatedData; }
Trying to compile a MUD (online text game) on Ubuntu 14.04 LTS & gcc 4.4.7 and I keep getting this: vt100.c: In function 'get_tactical_map': vt100.c:1741: warning: cast from pointer to integer of different size vt100.c:1805: warning: cast from pointer to integer of different size The code on each of the above lines is the same: *pto++ = 'a' + ((int) fch % 25); I can link the
试图在Ubuntu 14.04 LTS＆gcc 4.4.7上编译一个MUD（在线文本游戏），我一直在这样做： vt100.c：在函数'get_tactical_map'中： vt100.c：1741：警告：从指针转换为不同大小的整数 vt100.c：1805：警告：从指针转换为不同大小的整数 上述每一行代码都是相同的： *pto++ = 'a' + ((int) fch % 25); 如果需要，我可以链接整个文件，只是不知道在哪里上传它。 我猜你正试图编译由不知道或不关心64位系统上C语言
In the code snippet below, i get this warning - "warning: cast to pointer from integer of different size" in line number 25 which is the 3rd printf i do, printf("value of a thru struct ptr=%dn",(unsigned char *)m_arr(ptr_ns_type)[0]); I dont understand this warning since i do the same thing (except not using macros) in the 2nd printf printf("value of a thru ptr=%dn",(unsigned char)*p
在下面的代码片段中，我得到了这个警告 - “警告：投射到不同大小的整数的指针”在第25行，这是我做的第3个printf， printf("value of a thru struct ptr=%dn",(unsigned char *)m_arr(ptr_ns_type)[0]); 我不明白这个警告，因为我在第二个printf中做了同样的事情（除非不使用宏） printf("value of a thru ptr=%dn",(unsigned char)*ptr); 为此我没有得到任何错误。 任何人都可以帮助我理解这个警告吗？ 谢谢，巴德里。 #i
I am trying to use memcpy but it gives me a runtime error : Segmentation fault (Core dumped) and a compiler warning: warning: cast to pointer from integer of different size [-Wint-to-pointer-cast] this is the code unsigned char JMP[6] = {0xE9, 0x90, 0x90, 0x90, 0x90, 0xC3}; unsigned long JMPSize = ...; //copy jump size to jump instruction at second byte (this is where i get the error) mem
我正在尝试使用memcpy，但它给了我一个 运行时错误：分段错误（核心转储） 和一个编译器警告：警告：从不同大小的整数转换为指针[-Wint-to-pointer-cast] 这是代码 unsigned char JMP[6] = {0xE9, 0x90, 0x90, 0x90, 0x90, 0xC3}; unsigned long JMPSize = ...; //copy jump size to jump instruction at second byte (this is where i get the error) memcpy((uint8_t*)JMP[1],(void*)JMPSize, 4); JMP[1]和JMPSize是