In Android (Java) how do I print out a full stack trace? If my application crashes from nullPointerException or something, it prints out a (almost) full stack trace like so: java.io.IOException: Attempted read from closed stream. com.android.music.sync.common.SoftSyncException: java.io.IOException: Attempted read from closed stream. at com.android.music.sync.google.MusicSyncAdapter.getChang
在Android（Java）中，我如何打印出完整的堆栈跟踪？ 如果我的应用程序从nullPointerException或其他东西崩溃，它会打印出一个（几乎）完整的堆栈跟踪，如下所示： java.io.IOException: Attempted read from closed stream. com.android.music.sync.common.SoftSyncException: java.io.IOException: Attempted read from closed stream. at com.android.music.sync.google.MusicSyncAdapter.getChangesFromServerAsDom(Mus
This question already has an answer here: Get current stack trace in Java 21 answers You can use Apache commons to convert an Exception stack trace to String. This class is available in Apache commons-lang-2.2.jar: org.apache.commons.lang.exception.ExceptionUtils.getStackTrace(Throwable)
这个问题在这里已经有了答案： 在Java 21的答案中获取当前堆栈跟踪 您可以使用Apache公用程序将异常堆栈跟踪转换为字符串。 这个类在Apache commons-lang-2.2.jar中可用： org.apache.commons.lang.exception.ExceptionUtils.getStackTrace(Throwable)
Possible Duplicate: Get current stack trace in Java I have a method that saves messages to a file. This method is called from many different parts of my main program. Is there any way that I can generate the stack trace on demand, even though an Exception hasn't been triggered? For example, I was hoping for something like this... void saveMsg(String Msg) { if (a==b) Print Out Where
可能重复： 用Java获取当前堆栈跟踪 我有一个将消息保存到文件的方法。 这个方法从我的主程序的许多不同部分被调用。 即使没有触发Exception ，我是否可以按需生成堆栈跟踪？ 例如，我希望有这样的事情...... void saveMsg(String Msg) { if (a==b) Print Out Where This Method Was Called From [ like stackTrace in exception ] else saveMsgToFile(filePath,Msg); } 我知道Java可以在Exception堆栈跟踪，但是
This question already has an answer here: Get current stack trace in Java 21 answers You can output the stack trace to the current line like this: new Exception().printStackTrace(); Or if you need programmattic acces the the stacktrace elements you can use Thread.currentThread().getStackTrace() The only way I know of is to look at: StackTraceElement[] stackTraceElements = Thread.currentT
这个问题在这里已经有了答案： 在Java 21的答案中获取当前堆栈跟踪 您可以将堆栈跟踪输出到当前行，如下所示： new Exception().printStackTrace(); 或者，如果您需要编程访问您可以使用的堆栈跟踪元素 Thread.currentThread().getStackTrace() 我知道的唯一方法是看看： StackTraceElement[] stackTraceElements = Thread.currentThread().getStackTrace(); 虽然这听起来更像是一个logging问题，而不是实际观察呼叫跟
Can someone please provide an example of creating a Java ArrayList and HashMap on the fly? So instead of doing an add() or put() , actually supplying the seed data for the array/hash at the class instantiation? To provide an example, something similar to PHP for instance: $array = array (3, 1, 2); $assoc_array = array( 'key' => 'value' ); List<String> list = new ArrayList<String&g
有人可以提供一个实例来创建Java ArrayList和HashMap吗？ 所以，而不是做一个add()或put() ，实际上在类实例化中为数组/散列提供种子数据？ 举一个例子，例如类似于PHP的东西： $array = array (3, 1, 2); $assoc_array = array( 'key' => 'value' ); List<String> list = new ArrayList<String>() { { add("value1"); add("value2"); } }; Map<String,String> map = new HashMap<String,
I have an sample program as shown. I want my ArrayList symbolsPresent to be initialized with some predefined symbols: ONE, TWO, THREE, and FOUR. symbolsPresent.add("ONE"); symbolsPresent.add("TWO"); symbolsPresent.add("THREE"); symbolsPresent.add("FOUR"); import java.util.ArrayList; public class Test { private ArrayList<String> symbolsPresent = new ArrayList<String>(); p
我有一个示例程序如图所示。 我希望我的ArrayList symbolsPresent用一些预定义的符号进行初始化：ONE，TWO，THREE和FOUR。 symbolsPresent.add("ONE"); symbolsPresent.add("TWO"); symbolsPresent.add("THREE"); symbolsPresent.add("FOUR"); import java.util.ArrayList; public class Test { private ArrayList<String> symbolsPresent = new ArrayList<String>(); public ArrayList<String>
I need to initialize a constant HashMap and would like to do it in one line statement. Avoiding sth like this: hashMap.put("One", new Integer(1)); // adding value into HashMap hashMap.put("Two", new Integer(2)); hashMap.put("Three", new Integer(3)); similar to this in objective C: [NSDictionary dictionaryWithObjectsAndKeys: @"w",[NSNumber numberWithInt:1], @"K",[NSNumber numberWit
我需要初始化一个常量HashMap，并希望在一行语句中完成。 避免这样的事情： hashMap.put("One", new Integer(1)); // adding value into HashMap hashMap.put("Two", new Integer(2)); hashMap.put("Three", new Integer(3)); 与目标C中的类似： [NSDictionary dictionaryWithObjectsAndKeys: @"w",[NSNumber numberWithInt:1], @"K",[NSNumber numberWithInt:2], @"e",[NSNumber numberWithInt:4], @"z",[NSNumb
Java中的双括号初始化语法（ {{ ... }} ）是什么？ Double brace initialisation creates an anonymous class derived from the specified class (the outer braces), and provides an initialiser block within that class (the inner braces). eg new ArrayList<Integer>() {{ add(1); add(2); }}; Note that an effect of using this double brace initialisation is that you're creating anonymous inne
Java中的双括号初始化语法（ {{ ... }} ）是什么？ 双括号初始化创建一个从指定类（外括号）派生的匿名类，并在该类内提供一个初始化块（内括号）。 例如 new ArrayList<Integer>() {{ add(1); add(2); }}; 请注意，使用此大括号初始化的效果是您正在创建匿名内部类。 所创建的类有一个隐含的this指针到周围外部类。 虽然通常不是问题，但在某些情况下，例如在序列化或垃圾收集时，可能会导致悲伤，值得注意。
Conditions: do not modifiy the original lists; JDK only, no external libraries. Bonus points for a one-liner or a JDK 1.3 version. Is there a simpler way than: List<String> newList = new ArrayList<String>(); newList.addAll(listOne); newList.addAll(listTwo); 在我头顶，我可以缩短一行： List<String> newList = new ArrayList<String>(listOne); newList.addAll(listTwo); 在Jav
条件：不要修改原始列表; 只有JDK，没有外部库。 单线或JDK 1.3版本的奖励积分。 有没有比以下更简单的方法： List<String> newList = new ArrayList<String>(); newList.addAll(listOne); newList.addAll(listTwo); 在我头顶，我可以缩短一行： List<String> newList = new ArrayList<String>(listOne); newList.addAll(listTwo); 在Java 8中： List<String> newList = Stream.concat(listOn
This question already has an answer here: Efficiency of Java “Double Brace Initialization”? 15 answers Is this a variation of an anonymous inner class? 3 answers You're deriving an anonymous subclass of JPanel and then declaring a initialiser block for it. Here's the subclass: new JPanel(){}; Note the braces. And the initaliser is declared within it: new JPanel() { { /
这个问题在这里已经有了答案： Java“双Brace初始化”的效率？ 15个答案 这是一个匿名内部类的变体吗？ 3个答案 您正在派生JPanel的匿名子类，然后为其声明一个初始化块。 这是子类： new JPanel(){}; 注意大括号。 并且在其中宣布初始者： new JPanel() { { // static initaliser } }; 子类的派生只是为了允许初始化块。 这被称为双括号初始化，并且有些人担心为了这个目的而创建一个匿名类被滥用。 有