I've searched on this issue, and found many flavors and ideas but no real solutions. So, donning my asbestos suit and hoping for the best, I'm going to dare ask it again. I have managed C# code that calls managed C++ code, which in turn calls unmanaged C++ code. The unmanaged C++ code is throwing an exception, and I'd like to be able to debug through it. However, when I try to (e
我在这个问题上进行了搜索，发现了很多风味和想法，但没有真正的解决方案。 所以，穿上我的石棉西装，并希望最好的，我敢再问一遍。 我管理了调用托管C ++代码的C＃代码，后者又调用非托管C ++代码。 非托管C ++代码抛出异常，我希望能够通过它进行调试。 但是，当我尝试（明确地通过调用堆栈）加载符号时，我遇到了可怕的“符号文件MyFile.pdb与模块不匹配”的错误。 我猜测这是一个返回的通用错误代码，因为这些文件来自
I'm trying to create a simple C++ test application based off Qt 5.1 configure KMS functional test (qtbase/config.tests/qpa/kms), which is failing. The application is very simple as shown below: #include <stdlib.h> extern "C" { #include <gbm.h> #include <xf86drmMode.h> #include "xf86drm.h" } #include <EGL/egl.h> #include <GLES2/gl2.h> int main(int, char **) {
我试图创建一个基于Qt 5.1配置KMS功能测试（qtbase / config.tests / qpa / kms）的简单C ++测试应用程序，这是失败的。 该应用程序非常简单，如下所示： #include <stdlib.h> extern "C" { #include <gbm.h> #include <xf86drmMode.h> #include "xf86drm.h" } #include <EGL/egl.h> #include <GLES2/gl2.h> int main(int, char **) { // Check for gbm_surface which is quite a recent ad
Related to this question on CodeReview, I tried to use std::unordered_map with a custom allocator but apparently this does not work with gcc/clang and libstdc++. The error can be generated from initializing an empty hash map with a std::allocator #include <unordered_map> int main() { typedef std::allocator<std::pair<const int, int>> A; typedef std::unordered_map<in
与CodeReview上的这个问题有关，我尝试使用std::unordered_map与自定义分配器，但显然这不适用于gcc / clang和libstdc ++。 该错误可以通过使用std::allocator初始化一个空的哈希映射来生成 #include <unordered_map> int main() { typedef std::allocator<std::pair<const int, int>> A; typedef std::unordered_map<int, int, std::hash<int>, std::equal_to<int>, A> H;
I have a static-linked library which uses some functions from a dll which i need to delay-load. So in my executable's properties i've added this dll under Linker/Input/Delay Loaded DLLs . I can't add this option in the lib itself since it doesn't have the Linker property pages (because it's a static lib) So now whenever i use this lib in another executable tool i need to a
我有一个静态链接的库，它使用一些我需要延迟加载的dll函数。 所以在我的可执行文件的属性中，我在Linker/Input/Delay Loaded DLLs下添加了这个Linker/Input/Delay Loaded DLLs 。 我不能在lib本身中添加这个选项，因为它没有Linker属性页面（因为它是一个静态库） 所以现在每当我在另一个可执行工具中使用这个库时，我需要一遍又一遍地添加延迟加载选项，这是我想避免的。 我知道这里曾经有过一个杂注 #pragma comment(lin
This question already has an answer here: Why must we define both == and != in C#? 13 answers What are the basic rules and idioms for operator overloading? 7 answers
这个问题在这里已经有了答案： 为什么我们必须在C＃中定义==和！=？ 13个答案 运算符重载的基本规则和习惯用法是什么？ 7个答案
How can I add the bool operator== to the struct bd_addr_t ? I'm using this file within a C++ project. #ifndef APITYPES_H_ #define APITYPES_H_ #ifdef __GNUC__ #define PACKSTRUCT( decl ) decl __attribute__((__packed__)) #define ALIGNED __attribute__((aligned(0x4))) #else //msvc #define PACKSTRUCT( decl ) __pragma( pack(push, 1) ) decl __pragma( pack(pop) ) #define ALIGNED #endif typede
我如何将bool运算符==添加到struct bd_addr_t ？ 我在C ++项目中使用这个文件。 #ifndef APITYPES_H_ #define APITYPES_H_ #ifdef __GNUC__ #define PACKSTRUCT( decl ) decl __attribute__((__packed__)) #define ALIGNED __attribute__((aligned(0x4))) #else //msvc #define PACKSTRUCT( decl ) __pragma( pack(push, 1) ) decl __pragma( pack(pop) ) #define ALIGNED #endif typedef unsigned char uint8; typedef
I have been following some cpp exercises to learn cpp and I've run into a problem. I've created a class called "FixedPoint2" to implement a fixed point number to 2 decimals. I've included the header file which includes all the functions below. What I am struggling with is that when I try to test out the equality operator, I always get a false answer. In other words the
我一直在遵循一些cpp练习来学习cpp，而我遇到了一个问题。 我创建了一个名为“FixedPoint2”的类来实现2位小数的定点数。 我已经包含了包含以下所有功能的头文件。 我所苦苦挣扎的是，当我试图检验平等运算符时，我总是得到一个错误的答案。 换句话说，会发生以下情况： cout << (FixedPoint2(1.0)==FixedPoint2(1.0)) << endl; //returns true as expected cout << (FixedPoint2(1.2)==FixedPoint2(1.2))
Why can I not check two objects of classes with explicit constructor only for equality? The following code does not compile struct Foo { explicit Foo(int x) : x_(x) {} int x_; }; int main() { Foo(1) == Foo(1); } Do I have to declare operator == explicitly? You need to overload the equality operator== : struct Foo { explicit Foo(int x) : x_(x) {} int x_; }; bool operato
为什么我不能使用显式构造函数仅为平等检查两个类对象？ 以下代码不能编译 struct Foo { explicit Foo(int x) : x_(x) {} int x_; }; int main() { Foo(1) == Foo(1); } 我必须明确声明operator ==吗？ 你需要重载相等operator== ： struct Foo { explicit Foo(int x) : x_(x) {} int x_; }; bool operator==(Foo const &lhs, Foo const& rhs) { return lhs.x_ == rhs.x_; } 现场演示 编
Do I need to provide == and/or != operators? I've read here: Why don't C++ compilers define operator== and operator!=? that I do but when I actually tried it (didn't provide them and tried to use them) the program compiled fine. So what's going on? Using VS2010 if it matters. These operators are defined for fundamental, language-defined types, not for your custom ones. So
我是否需要提供==和/或！=运算符？ 我在这里读到：为什么C ++编译器不定义运算符==和运算符！=？ 我做了，但是当我真正尝试了它（没有提供它们并试图使用它们），程序编译得很好。 发生什么了？ 使用VS2010，如果它很重要。 这些运算符是为基本的，语言定义的类型定义的，而不是为您的定制类型定义的。 例如，它将适用于int s。 但不会为class foo; 除非你明确地提供它们 - 如果你没有告诉它如何去做，编译器不知道如
if (find(visitable.begin(), visitable.end(), ourstack.returnTop())) { ... } I want to determine whether the top character in stack ourstack can be found in the vector visitable . If yes, I want this character to be deleted from visitable . How would I code that? I know vectors use erase , but that requires the specific location of that character (which I don't know). This is for my maze
if (find(visitable.begin(), visitable.end(), ourstack.returnTop())) { ... } 我想，以确定是否在栈上的字符ourstack可以在载体中找到visitable 。 如果是的话，我希望这个角色从visitable被删除。 我将如何编码？ 我知道载体使用erase ，但这需要该字符的具体位置（我不知道）。 这是为了我的迷宫寻路工作。 另外，我的returnTop给我一个错误： class "std.stack<char..." has no member returnTop 。