I need to check if the thread running a certain piece of code is the main (UI) thread or not. How can I achieve this? Looper.myLooper() == Looper.getMainLooper() 如果这返回true，那么你在UI线程上！ you can use below code to know if current thread is UI/Main thread or not if(Looper.myLooper() == Looper.getMainLooper()) { // Current Thread is Main Thread. } or you can also use this if(Loope
我需要检查运行某段代码的线程是否是主（UI）线程。 我怎样才能做到这一点？ Looper.myLooper() == Looper.getMainLooper() 如果这返回true，那么你在UI线程上！ 你可以使用下面的代码来知道当前线程是否是UI /主线程 if(Looper.myLooper() == Looper.getMainLooper()) { // Current Thread is Main Thread. } 或者你也可以使用这个 if(Looper.getMainLooper().getThread() == Thread.currentThread()) { // Current
I want to be able to call the following method after a specified delay. In objective c there was something like: [self performSelector:@selector(DoSomething) withObject:nil afterDelay:5]; Is there an equivalent of this method in android with java? For example I need to be able to call a method after 5 seconds. public void DoSomething() { //do something here } 更好的版本： final Handler
我希望能够在指定的延迟后调用以下方法。 在目标c中有这样的东西： [self performSelector:@selector(DoSomething) withObject:nil afterDelay:5]; 有没有这种方法在Android与Java的等价物？ 例如，我需要能够在5秒后调用一个方法。 public void DoSomething() { //do something here } 更好的版本： final Handler handler = new Handler(); handler.postDelayed(new Runnable() { @Override public void run() {
I've worked/seen a few spring-hibernate web application projects having as many interfaces as there are actual service and dao classes. I always thought that these two as the main reasons for having these single implementation interfaces: Spring can wire actual implementation as dependencies in a given class (loose coupling) public class Person { @Autowired private Address addr
我曾经/看过几个Spring-hibernate Web应用程序项目，它们具有与实际服务和dao类相同的接口。 我一直认为这两个是拥有这些单一实现接口的主要原因： Spring可以将实际实现作为给定类中的依赖关系（松耦合） public class Person { @Autowired private Address address; @Autowired private AccountDetail accountDetail; public Person(Address address, AccountDetail accountDetail) { // co
I haven't touched Java since using JBuilder in the late 90's while at University, so I'm a little out of touch - at any rate I've been working on a small Java project this week, and using Intellij IDEA as my IDE, for a change of pace from my regular .Net development. I notice it has support for adding interfaces and @interfaces, what is an @interface, and how does it differ from
自从90年代末在大学使用JBuilder以来，我一直没有碰过Java，所以我有点失去联系 - 无论如何，本周我一直在研究一个小型Java项目，并使用Intellij IDEA作为我的IDE ，从我的常规.Net开发中改变步伐。 我注意到它支持添加接口和@interface，什么是@interface，它与普通接口有什么不同？ public interface Test { } 与 public @interface Test { } 我已经做了一些搜索，但找不到涉及@interface的大量有用信息。 @符号表示注
It's likely that the particular font you're using doesn't contain a glyph for that character. Try switching to another font.
很可能您使用的特定字体不包含该字符的字形。 尝试切换到另一种字体。
I have a decimal (not hexadecimal) color code and, using Java, I need to convert it to the three RGB colors. So for example, 16777215 (pure white) needs to get converted to Red: 255 Green: 255 Blue: 255. 65280 (pure green) needs to get converted to Red: 0 Green 255: Blue: 0 Here is a converter for more examples. Just doing some small calculations and playing with the calculator on the pag
我有一个十进制（不是十六进制）颜色代码，使用Java，我需要将它转换为三种RGB颜色。 例如，16777215（纯白色）需要转换为红色：255绿色：255蓝色：255。 需要将65280（纯绿色）转换为红色：0绿色255：蓝色：0 这是一个转换器的更多例子。 只是做一些小计算，并在上面链接的页面上用计算器玩，我已经确定： 红色等于65536（256 ^ 2） （255x65536 = 16711680，又名纯红色） 绿色等于256（256 ^ 1） （255x256 =
In my Java application, I was able to get the value of JButton color in terms of Red, Green, Blue values; I have stored these values in three integers. How to convert RGB values into the equivalent hexadecimal value? Example of that like in this format #0033fA You can use String hex = String.format("#%02x%02x%02x", r, g, b); Use capital X's if you want your resulting hex-digits to
在我的Java应用程序中，我能够根据红色，绿色和蓝色值获得JButton颜色的值; 我用三个整数存储了这些值。 如何将RGB值转换为等效的十六进制值？ 这种格式的#0033fA 您可以使用 String hex = String.format("#%02x%02x%02x", r, g, b); 如果您希望将生成的十六进制数字大写（ #FFFFFF与#ffffff ），请使用大写X。 一个班轮，但没有String.format： Color your_color = Color.BLACK; String hex = "#"+Integer.toHexS
How can I convert hex color to RGB code in Java? Mostly in Google, samples are on how to convert from RGB to hex. 我想这应该做到这一点： /** * * @param colorStr e.g. "#FFFFFF" * @return */ public static Color hex2Rgb(String colorStr) { return new Color( Integer.valueOf( colorStr.substring( 1, 3 ), 16 ), Integer.valueOf( colorStr.substring( 3, 5 ), 16 ),
如何在Java中将十六进制颜色转换为RGB代码？ 主要在谷歌，样本是如何从RGB转换为十六进制。 我想这应该做到这一点： /** * * @param colorStr e.g. "#FFFFFF" * @return */ public static Color hex2Rgb(String colorStr) { return new Color( Integer.valueOf( colorStr.substring( 1, 3 ), 16 ), Integer.valueOf( colorStr.substring( 3, 5 ), 16 ), Integer.valueOf( colorS
I have an app where I need to move stacks of buttons (just like moving part of a stack of cards from one pile to another). I have defined all the buttons in an xml layout and setup touch and drag listeners for all. I can drag and drop any button around the screen individually. but what I need to do in some cases is drag the other buttons stacked on top of the original button I clicked at the s
我有一个应用程序，需要移动按钮堆栈（就像将一堆卡片的一部分从一堆移动到另一堆一样）。 我已经在xml布局中定义了所有按钮，并为所有人设置了触摸和拖动监听器。 我可以单独拖放屏幕上的任何按钮。 但在某些情况下我需要做的是拖动堆叠在我同时单击的原始按钮顶部的其他按钮。 有没有一种方法来“欺骗”或模拟另一个按钮被按下（所以监听器注册它）？ 谢谢***编辑9/8/15 @Override public boolean onTouch（View v，MotionE
I am trying to create a connection for my spring project, soemthing very simple. I want to create the configuration fields on my application.properties. I tried with the spring.datasource and I dont get any error, but still, I dont get any info, just null pointers... I think the connections have not been made properly. Here is part of my pom, with this dependencies: <dependency>
我正在尝试为我的spring项目创建一个连接，这非常简单。 我想在我的application.properties上创建配置字段。 我试着用spring.datasource ，但没有得到任何错误，但仍然没有得到任何信息，只是空指针...我认为连接没有做好。 这是我的一部分，有这种依赖： <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-data-jpa</artifactId>