I followed this tutorial but it seems that it is kind out of date? I'm not sure. Unfortunately I'm not very experienced with Java (but with C#, Python, ..) so maybe there is something obvious I did not regard. IntelliJ is giving me import errors for libraries from the com.badlogic.gdx package import com.badlogic.gdx.ApplicationAdapter; import com.badlogic.gdx.Gdx; import com.badlogi
我遵循这个教程，但似乎它是过时的？ 我不确定。 不幸的是，我对Java不熟悉（但是使用C＃，Python，..），所以也许有些事情我不明白。 IntelliJ给我导入来自com.badlogic.gdx包的库的导入错误 import com.badlogic.gdx.ApplicationAdapter; import com.badlogic.gdx.Gdx; import com.badlogic.gdx.graphics.GL20; import com.badlogic.gdx.graphics.Texture; import com.badlogic.gdx.graphics.g2d.SpriteBatch; java：pa
Possible Duplicate: Can we convert a byte array into an InputStream in Java? There is a way to convert an array of bytes ( byte[] ) to InputStream in Java? I looked at some methods in Apache Commons IO, but found nothing. ByteArrayInputStream扩展了InputStream ： InputStream myInputStream = new ByteArrayInputStream(myBytes); 也许你想要一个ByteArrayInputStream？ 应该很容易在javadoc中找到...
可能重复： 我们可以在Java中将字节数组转换为InputStream吗？ 有一种方法可以将字节数组（ byte[] ）转换为Java中的InputStream？ 我查看了Apache Commons IO中的一些方法，但没有发现任何内容。 ByteArrayInputStream扩展了InputStream ： InputStream myInputStream = new ByteArrayInputStream(myBytes); 也许你想要一个ByteArrayInputStream？ 应该很容易在javadoc中找到... byte[] byteArr = new byte[] { 0xC, 0xA
I used a variable with a lot of data in it, say String data . I wanted to use a small part of this string in the following way: this.smallpart = data.substring(12,18); After some hours of debugging (with a memory visualizer) I found out that the objects field smallpart remembered all the data from data , although it only contained the substring. When I changed the code into: this.smallpart
我使用了一个有很多数据的变量，比如String data 。 我想用下面的方式使用这个字符串的一小部分： this.smallpart = data.substring(12,18); 经过几个小时的调试（使用内存可视化工具）后，我发现objects field smallpart记住了所有来自data ，尽管它只包含子字符串。 当我将代码更改为： this.smallpart = data.substring(12,18)+""; 问题解决了！ 现在我的应用程序现在使用的内存很少！ 这怎么可能？ 任何人都可以
I have a Java server that is listening requests, and a PHP page that is sending those requests. Once I am connected to the server, I write something with the "socket_write" command, and then I try to read the server answer with "socket_read". (instead of waiting for answers, I would like to know how to synchronise the two programs correctly, with semaphore for example). H
我有一个正在侦听请求的Java服务器和一个发送这些请求的PHP页面。 一旦我连接到服务器，我用“socket_write”命令写入内容，然后尝试使用“socket_read”读取服务器答案。 （而不是等待答案，我想知道如何正确地同步两个程序，例如信号量）。 代码如下： $socket = socket_create(AF_INET,SOCK_STREAM,SOL_TCP); $con = socket_connect($socket, "127.0.0.1",6543); //Connected, we can ask $message = "SLICE"; socket_wr
I'm trying to learn java socket programming, but I have a trouble with the read function of InputStream. At first, I created a socket to connect to the server. After the connection is established, the server then send back the message that "the connection is established" and the read function is work fine. Then I tried to send byte message to the server, but I can't read the
我正在尝试学习java套接字编程，但是我在InputStream的读取功能方面遇到了问题。 起初，我创建了一个连接到服务器的套接字。 建立连接后，服务器将发回“连接已建立”的消息，并且读取功能正常工作。 然后我尝试向服务器发送字节消息，但是我无法从InputStream读取数据，因为我的程序停留在“in.read（buf）”行。 任何人都可以指出我如何解决这个问题。 Socket client = new Socket("xxx.xxx.xxx.xxx", 45000); InputStream
I am on the stage of development, where I have two modules and from one I got output as a OutputStream and second one, which accepts only InputStream . Do you know how to convert OutputStream to InputStream (not vice versa, I mean really this way) that I will be able to connect these two parts? Thanks An OutputStream is one where you write data to. If some module exposes an OutputStream , t
我处于开发阶段，我有两个模块，从一个输出为OutputStream ，另一个输出为InputStream 。 你知道如何将OutputStream转换为InputStream （反之亦然，我的意思是这样），我将能够连接这两部分？ 谢谢 OutputStream是你写数据的地方。 如果某个模块公开一个OutputStream ，则期望在另一端读取某些内容。 另一方面，暴露InputStream事情表明您需要监听这个流，并且会有可读的数据。 所以可以将InputStream连接到OutputStre
如何通过Java读取文件夹中的所有文件？ public void listFilesForFolder(final File folder) { for (final File fileEntry : folder.listFiles()) { if (fileEntry.isDirectory()) { listFilesForFolder(fileEntry); } else { System.out.println(fileEntry.getName()); } } } final File folder = new File("/home/you/Desktop"); listFilesForFolder(folder); Files.
如何通过Java读取文件夹中的所有文件？ public void listFilesForFolder(final File folder) { for (final File fileEntry : folder.listFiles()) { if (fileEntry.isDirectory()) { listFilesForFolder(fileEntry); } else { System.out.println(fileEntry.getName()); } } } final File folder = new File("/home/you/Desktop"); listFilesForFolder(folder); Files
Specifically, the problem is to write a method like this: int maybeRead(InputStream in, long timeout) where the return value is the same as in.read() if data is available within 'timeout' milliseconds, and -2 otherwise. Before the method returns, any spawned threads must exit. To avoid arguments, the subject here java.io.InputStream, as documented by Sun (any Java version). Please n
具体来说，问题是写一个像这样的方法： int maybeRead(InputStream in, long timeout) 如果数据在'timeout'毫秒内可用，则返回值与in.read（）相同，否则为-2。 在方法返回之前，任何派生线程都必须退出。 为了避免争论，这里的主题java.io.InputStream，由Sun（任何Java版本）记录。 请注意，这不像看起来那么简单。 以下是Sun的文档直接支持的一些事实。 in.read（）方法可能是不可中断的。 在Reader或Inte
What's the difference between: InputStream is = this.getClass().getClassLoader().getResourceAsStream(fileName) and InputStream is = Thread.currentThread().getContextClassLoader().getResourceAsStream(fileName) and InputStream is = this.getClass().getResourceAsStream(fileName) When are each one more appropriate to use than the others? The file that I want to read is in the classpath as
有什么区别： InputStream is = this.getClass().getClassLoader().getResourceAsStream(fileName) 和 InputStream is = Thread.currentThread().getContextClassLoader().getResourceAsStream(fileName) 和 InputStream is = this.getClass().getResourceAsStream(fileName) 什么时候比其他人更适合使用？ 我想要读取的文件在类路径中作为读取文件的类。 我的类和文件位于同一个jar中，并打包在EAR文件中，并部署在Web
Suppose I have an InputStream that contains text data, and I want to convert this to a String (for example, so I can write the contents of the stream to a log file). What is the easiest way to take the InputStream and convert it to a String ? public String convertStreamToString(InputStream is) { // ??? } 这是我的版本， public static String readString(InputStream inputStream) throws IOExce
假设我有一个包含文本数据的InputStream ，并且我想将它转换为一个String （例如，所以我可以将流的内容写入日志文件）。 采用InputStream并将其转换为String的最简单方法是什么？ public String convertStreamToString(InputStream is) { // ??? } 这是我的版本， public static String readString(InputStream inputStream) throws IOException { ByteArrayOutputStream into = new ByteArrayOutputStream();