This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers 尝试这个： scalavars.ExchangeValue = str(float(scalavars.CurrencyAmount) / float(scalavars.Rate))
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 尝试这个： scalavars.ExchangeValue = str(float(scalavars.CurrencyAmount) / float(scalavars.Rate))
This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers Change your first line to usernum = int(input('Enter a number, Ill determine if its pos, neg, OR Zero.')) As you had it, usernum is a string value, since input() always returns strings in Python 3.x, and you were trying to compare it to integers. So convert it to an integer first. I
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 改变你的第一行 usernum = int(input('Enter a number, Ill determine if its pos, neg, OR Zero.')) 就像你usernum ， usernum是一个字符串值，因为input()总是返回Python 3.x中的字符串，并且你试图将它与整数进行比较。 所以先把它转换成一个整数。 我通过用int()类型转换来包围input调用来做到这一点。 请注意，如果用户输入的
This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers >>> old = {'Georgia': ['18', '13', '8', '14']} >>> new = {key: list(map(int, value)) for key, value in old.items()} >>> new {'Georgia': [18, 13, 8, 14]} You can do this: map is taking the values from the iterable in this case the value of the dictionaries ke
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 >>> old = {'Georgia': ['18', '13', '8', '14']} >>> new = {key: list(map(int, value)) for key, value in old.items()} >>> new {'Georgia': [18, 13, 8, 14]} 你可以这样做： map在这种情况下将迭代器中的值作为字典键的值，并将迭代器中的每个项都转换为int 。 map返回一个地图对象而不是一个list所
This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers what you are doing is like following: a = ['1','3','10','5'] print sorted(a) output ['1', '10', '3', '5'] therefore the first step is converting to float/int a = ['1','3','10','5'] print sorted(a) print sorted(map(int,a)) print max(a) print max(map(int,a)) output ['1', '10', '3',
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 你在做什么就像下面这样： a = ['1','3','10','5'] print sorted(a) 产量 ['1', '10', '3', '5'] 因此第一步转换为float / int a = ['1','3','10','5'] print sorted(a) print sorted(map(int,a)) print max(a) print max(map(int,a)) 产量 ['1', '10', '3', '5'] [1, 3, 5, 10] 5 10
This question already has an answer here: How can I convert a string to an int in Python? 7 answers How do I parse a string to a float or int in Python? 22 answers times = int(raw_input('Enter a number: ')) If someone enters in something other than an integer, it will throw an exception. If that's not what you want, you could catch the exception and handle it yourself, like this: tr
这个问题在这里已经有了答案： 如何将字符串转换为Python中的int？ 7个答案 如何在Python中将字符串解析为float或int？ 22个答案 times = int(raw_input('Enter a number: ')) 如果某人输入的不是整数，它会抛出异常。 如果这不是你想要的，你可以捕获异常并自己处理，如下所示： try: times = int(raw_input('Enter a number: ')) except ValueError: print "An integer is required." 如果你想继续询问输入
This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers You could try to cast to an int, and repeat the question if it fails. i = 1 while True: timeNum = input("How many times do you want to repeat the sequence?") try: timeNum = int(timeNum) break except ValueError: pass while i <= timeNum: ...
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 您可以尝试将其转换为int，如果失败则重复该问题。 i = 1 while True: timeNum = input("How many times do you want to repeat the sequence?") try: timeNum = int(timeNum) break except ValueError: pass while i <= timeNum: ... i += 1 虽然使用try-catch进行处理在某些语言中是
This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers Wrap your input in either int or float number=int(input("Enter a number to multiply by 9 ")) or number=float(input("Enter a number to multiply by 9 ")) This is done because input accepts strings and you have to convert these to numerals.
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 将input包裹为int或float number=int(input("Enter a number to multiply by 9 ")) 要么 number=float(input("Enter a number to multiply by 9 ")) 这是因为input接受字符串，你必须将它们转换为数字。
This question already has an answer here: How do I parse a string to a float or int in Python? 22 answers Your line should be pi_float = float(pi_string) float(pi_string) is a float value, you can not assign to it, because it is not a variable. 如果pi_string = "3.1415926" float()方法将为您执行此操作。 >>>pi_float = float(pi_string) >>>type(pi_float) <class '
这个问题在这里已经有了答案： 如何在Python中将字符串解析为float或int？ 22个答案 你的行应该是pi_float = float(pi_string) float(pi_string)是一个浮点值，你不能指定它，因为它不是一个变量。 如果pi_string = "3.1415926" float()方法将为您执行此操作。 >>>pi_float = float(pi_string) >>>type(pi_float) <class 'float'>
Possible Duplicate: Python - Parse String to Float or Int How can I convert '1.03' (string) to a number in Python, preferably a decimal ? Just use float() >>> float('1.03') 1.03 If you need an actual Decimal type, use the decimal module: >>> from decimal import * >>> Decimal('1.03') Decimal('1.03') In general, using floats will be easier for you, but y
可能重复： Python - 将字符串解析为Float或Int 如何将'1.03'（字符串）转换为Python中的数字，最好是小数？ 只需使用float() >>> float('1.03') 1.03 如果您需要实际的Decimal类型，请使用decimal模块： >>> from decimal import * >>> Decimal('1.03') Decimal('1.03') 一般来说，使用浮点数对于你来说会更容易，但是你花费的精度与浮点数不符。 float ， int和decimal可以自
Possible Duplicate: How do I check if a string is a number in Python? Python - Parse String to Float or Int For example, I want to check a string and if it is not convertible to integer(with int() ), how can I detect that? Use the .isdigit() method: >>> '123'.isdigit() True >>> '1a23'.isdigit() False Quoting the documentation: Return true if all characters in the str
可能重复： 如何检查字符串是否是Python中的数字？ Python - 将字符串解析为Float或Int 例如，我想检查一个字符串，如果它不能转换为整数（与int() ），我怎么能检测到？ 使用.isdigit()方法： >>> '123'.isdigit() True >>> '1a23'.isdigit() False 引用文档： 如果字符串中的所有字符都是数字并且至少有一个字符，则返回true，否则返回false。 对于unicode字符串或Python 3字符串，您需要使