Possible Duplicate: Static methods in Python? I think my question is pretty straight forward, but to be more clear I'm just wondering, i have this : class MyBrowser(QWebPage): ''' Settings for the browser.''' def __init__(self): QWebPage.__init__(self) pass def userAgentForUrl(self, url=None): ''' Returns a User Agent that will be seen by the website
可能重复： Python中的静态方法？ 我认为我的问题非常简单，但要更清楚我只是想知道，我有这个： class MyBrowser(QWebPage): ''' Settings for the browser.''' def __init__(self): QWebPage.__init__(self) pass def userAgentForUrl(self, url=None): ''' Returns a User Agent that will be seen by the website. ''' return "Mozilla/5.0 (Windows NT 6.2; WOW64) Appl
In Python, I am using uuid4() method to create a unique char set. But I can not find a way to limit that to 10 or 8 characters. Is there any way? uuid4() ffc69c1b-9d87-4c19-8dac-c09ca857e3fc Thanks. Try : x = uuid4() str(x)[:8] Output : "ffc69c1b" Is there a way to substring a string in Python?
在Python中，我使用uuid4（）方法创建一个唯一的字符集。 但我找不到一种方法将其限制为10或8个字符。 有什么办法吗？ uuid4() ffc69c1b-9d87-4c19-8dac-c09ca857e3fc 谢谢。 尝试： x = uuid4() str(x)[:8] 输出： "ffc69c1b" 有没有办法在Python中对字符串进行子串处理？
I have a big number lets say of around hundred digits. I want to subset that big number into consecutive number of 5 digits and find the product of those 5 digits. For example my first 5 digit number would be 73167. I need to check the product of the individual numbers in 73167 and so on. The sample number is as follows: 73167176531330624919225119674426574742355349194934969835203127745063262
我有一个很大的数字可以说约百位数。 我想把这个大数字分成连续的5位数字并找出这5位数字的乘积。 例如，我的第一个5位数字是73167.我需要检查73167中各个数字的乘积等等。 样本编号如下： 73167176531330624919225119674426574742355349194934969835203127745063262395783180169848018694788518438586156078911294949545950173795833195285320880551112540698747158523863050715693290963295227443043557 我有一个问题，
How do I print a specific character from a string in Python? I am still learning and now trying to make a hangman like program. The idea is that the user enters one character, and if it is in the word, the word will be printed with all the undiscovered letters as "-". I am not asking for a way to make my idea/code of the whole project better, just a way to, as i said, print that one
如何从Python中的字符串打印特定的字符？ 我仍然在学习，现在正在努力让一个像项目一样的hang子手。 这个想法是，用户输入一个字符，如果它在单词中，该单词将被打印所有未发现的字母为“ - ”。 我并没有要求让整个项目的想法/代码更好，只是一种方法，就像我说的那样，打印出字符串的一个特定字符。 print(yourstring[characterposition]) 例 print("foobar"[3]) 打印字母b 编辑： mystring = "hello world" lookingf
I have a string similar to "dasdasdsafs[image : image name : image]vvfd gvdfvg dfvgd" . From this string, I want to remove the part which stars from [image : and ends at : image] . I tried to find the 'sub-string' using following code- result = re.search('%s(.*)%s' % (start, end), st).group(1) but it doesn't give me the required result. Help me to find the correct way t
我有一个类似于"dasdasdsafs[image : image name : image]vvfd gvdfvg dfvgd" 。 从这个字符串中，我想删除[image :和结束于: image]星星的部分。 我尝试使用以下代码查找“子字符串” result = re.search('%s(.*)%s' % (start, end), st).group(1) 但它没有给我所需的结果。 帮助我找到从字符串中删除子字符串的正确方法。 你可以使用re.sub ： >>> s='dasdasdsafs[image : image name : image]vvfd gvdf
This question already has an answer here: Is there a way to substring a string in Python? 10 answers >>> s = "ABCDEFGH135791011" >>> print s[:7] ABCDEFG
这个问题在这里已经有了答案： 有没有办法在Python中对字符串进行子串处理？ 10个答案 >>> s = "ABCDEFGH135791011" >>> print s[:7] ABCDEFG
This question already has an answer here: Is there a way to substring a string in Python? 10 answers Understanding Python's slice notation 29 answers You can use this syntax called slices s = 'gorilla' s[2:] will return 'rilla' see also Explain Python's slice notation
这个问题在这里已经有了答案： 有没有办法在Python中对字符串进行子串处理？ 10个答案 了解Python的切片符号29个答案 您可以使用这种称为切片的语法 s = 'gorilla' s[2:] 将返回 'rilla' 另请参阅解释Python的切片符号
This question already has an answer here: Is there a way to substring a string in Python? 10 answers You can do this using Python's slice notation: >>> mystr = 'foo7bar' >>> mystr[:mystr.index('7')] 'foo' >>> The format for slice notation is [start:stop:step] . The index method of a string finds the position of the first occurrence of its input. Note howev
这个问题在这里已经有了答案： 有没有办法在Python中对字符串进行子串处理？ 10个答案 你可以使用Python的切片符号来做到这一点： >>> mystr = 'foo7bar' >>> mystr[:mystr.index('7')] 'foo' >>> 切片符号的格式为[start:stop:step] 。 字符串的index方法查找其输入的第一次出现的位置。 但请注意，如果您正在处理更复杂的事情（例如匹配模式），则可能需要查看正则表达式。 尽管如此，
This question already has an answer here: Is there a way to substring a string in Python? 10 answers You must use output[begin:end] , not output[begin, end] (that's just how the syntax for slicing ordinary strings/lists/etc works). So: minusStuffBeforeReqPer = output[reqPerIndx:len(output)] However, this is redundant. So you should instead probably do this: minusStuffBeforeReqPer =
这个问题在这里已经有了答案： 有没有办法在Python中对字符串进行子串处理？ 10个答案 你必须使用output[begin:end] ，而不是output[begin, end] （这只是如何切片普通字符串/列表/等工作的语法）。 所以： minusStuffBeforeReqPer = output[reqPerIndx:len(output)] 但是，这是多余的。 所以你应该改为这样做： minusStuffBeforeReqPer = output[reqPerIndx:] 通过省略切片的end部分，切片将一直到output结束。 因
This question already has an answer here: Is there a way to substring a string in Python? 10 answers I'll try to guess expected result: def printThree(str): for i in range(0, len(str), 3): print str[i:i+3] Output >>> printThree("somestring") som est rin g Use slicing: def PrintThree(string): return string[:3] This runs as: >>> PrintThree('abcde')
这个问题在这里已经有了答案： 有没有办法在Python中对字符串进行子串处理？ 10个答案 我会尝试猜测预期的结果： def printThree(str): for i in range(0, len(str), 3): print str[i:i+3] 产量 >>> printThree("somestring") som est rin g 使用切片： def PrintThree(string): return string[:3] 这个运行如下： >>> PrintThree('abcde') 'abc' >>> PrintThree('hello